Question

2y²-y+2=0 Find the value of discriminant for this equation.

Answer 1

Hey!

Here is your answer!
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QUADRATIC EQUATION :

2y²-y+2=0

Comparing it with ax²+bx+c=0

We get,

a=2, b= -1 and c=2

Now, we know that
$discriminant \: (d) = {b}^{2} - 4ac \\ \\ d = { (- 1)}^{2} - 4 \times 2 \times 2 \\ \\ d = 1 - 16 \\ \\ d = - 15$
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So the discriminant of this equation is -15.
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Hope it's satisfactory!!!

Answer 2

2y^2 - y + 2 = 0 


Here,

a = 2
b = - 1 
y = 2 




We know,Discriminant = b^2 - 4ac 
                                       = (-1)^2 - 4(2)(2)
                                       = 1 - 16 
                                       = -15