Question

The roots of x²+kx+k=0
are real and
equal them k=
​

Answer 1

Answer:

Given, x²+kx+k=0

We know if roots are real and equal then D = 0

=> b² - 4ac = 0

=> (k)² - 4(1)(k) = 0

=> k² - 4k = 0

=> k( k - 4 ) = 0

=> k = 0 or k - 4 = 0

=> k = 4

So, k = 0 or 4