Question

The rotation of the earth about its axis speeds up such that a man on the equator becomes weightness. In such a situation, what would be the duration of one day ?

Answer 1

Answer:

Explanation:

Here balancing forces,

Normal force+centrifugal force due tot earth's rotation=gravitational force.

Here, normal force is zero.

So, mg=mω  

2

R⇒ω=  

g/R

​  

 

where m is the mass of the object, and R is the radius of planet.

The time period or duration of one day is then, T=2π/ω=2π  

​

Answer 2

Answer:

Insted of wasting your time here. You can see answer key of Every Aakash Test in this YouTube Channel.

Steps to do:-

1)Copy this text ↓

UC5kxeAOLXn4R5OL28-50ENQ

2)Paste it on YouTube search box.

3)You will see a channel named Gorav Sharma. Subscribe it(optional)

4)Here You will find all Answer Keys of Aakash Tests.

Share with all Aakashians You know.

Best of luck for your upcoming tests

Explanation:

By the way answer is

$\pi \sqrt{r \div 2}$