Physics, asked by roysahabji, 11 months ago

The rotational kinetic energy of two moles of monatomic gas at 27°C is equal to

(1) 400 R
(2) 1200 R
(3) 300 R
(4) Zero

Answer=(4)​

Answers

Answered by Anonymous
4

Explanation:

The rotational kinetic energy of two moles of monatomic gas at 27°C is equal to

(1) 400 R

(2) 1200 R

(3) 300 R

(4) Zero✔️✔️✔️✔️

Answered by Anonymous
14

Answer:

Explanation:

Explanation:The rotational kinetic energy of two moles of monoatomic gas at 27°C is equal to

(4) Zero√

@#0peless

Similar questions