The rotational kinetic energy of two moles of monatomic gas at 27°C is equal to
(1) 400 R
(2) 1200 R
(3) 300 R
(4) Zero
Answer=(4)
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Answered by
4
Explanation:
The rotational kinetic energy of two moles of monatomic gas at 27°C is equal to
(1) 400 R
(2) 1200 R
(3) 300 R
(4) Zero✔️✔️✔️✔️
Answered by
14
Answer:
Explanation:
Explanation:The rotational kinetic energy of two moles of monoatomic gas at 27°C is equal to
(4) Zero√
@#0peless
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