Question

The rotational kinetic energy of two moles of monatomic gas at 27°C is equal to (1) 400 R(2) 1200 R(3) 300 R(4) ZeroAnswer=(4)​

Answer 1

The required option is (D) zero.

Explanation:

A monoatomic ideal gas has negligible rotational kinetic energy, from the fact that the atom is very tiny and its moment of inertia is very small. Thus , in Kinetic Theory of Gases, monoatomic gases are considered to have only tramslational energy.

The required option is (D) zero.

Hence, the rotational kinetic energy of two moles of monatomic gas at 27°C is equal to zero(0).

Answer 2

Answer: Zero

Explanation: As the gas is mono-atomic , so it doesn't possess rotational degree of freedom, and as we know , KE = (f/2)kt

So as f = 0 ; Rotational KE =0