Physics, asked by CapyltainNJ1606, 8 months ago

The rubber cord of a catapult has cross-section area 1 mm^(2) and a total unstretched length 10 cm. It is stretched to 12 cm and then released to project a partical of mass 5 g. Calculate the velocity of projection (Y for rubber is 5xx10^(8)N//m^(2))

Answers

Answered by Anonymous
0

Answer:

Explanation:

A rubber cord catapult has a cross sectional area

The rubber cord of a catapult has a cross-sectional area 1mm2 and total unstretched length 10cm. It is stretched to 12cm and then released to project a missile of mass 5gm

Similar questions