the runs scored by a player in a season are 1,10,39,27,51,0,85,91,101 ; find
1. range of runs scored.
2. median score.
3. average score per inning of player.
Answers
Answer:
Step-by-step explanation:
. The batting average for
40
innings of a cricket player is
50
runs. His highest score exceeds his lowest score by
172
runs. If these two innings are excluded, the average of the remaining
38
innings is
48
runs. Find out the highest score of the player.
A.
166
B.
174
C.
180
D.
150
Answer: Option B
Explanation:
Solution 1
Total runs scored in
40
innings
=
40
×
50
After excluding two innings, total runs scored in remaining
38
innings
=
38
×
48
Sum of the scores of the excluded innings
=
40
×
50
−
38
×
48
=
176
Given that the scores of the excluded innings differ by
172.
Hence let's take the highest score as
x
+
172
and lowest score as
x
x
+
172
+
x
=
176
⇒
2
x
=
4
⇒
x
=
2
Highest score
=
x
+
172
=
2
+
172
=
174
Solution 2
As per the formula, sum of scores of excluded innings
=
2
×
50
+
2
(
40
−
2
)
=
176
⇒
highest score + (highest score
−
172
)
=
176
⇒
highest score
=
174