Question

The S.T of soap water is 2.1x10² N/m.
what work will have to done in blowing a
soap beebble of diameter 0.03m.?​

Answer 1

The amount of work done in blowing the bubble is 1.1869 J

Explanation:

Given data:

Radius of bubble "r" = d/2 = 0.03 m/2 = 0.015 m

Surface tension of soap water = 2.1 x 10² N/m

Increase in surface area = dS = 8πr^2

                                         = 8 x 3.14 x (0.015)^2

                                         = 0.005652 = 5.652 x 10^-3 m^2

Work done = σ ×dS

                   = 2.1 x 10² x 5.652 x 10^-3

                   = 11.869 x 10^-1 = 1.1869 J

Thus the amount of work done in blowing the bubble is 1.1869 J

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