Question

The salaries of a and b together is rs. 14,000. A spend 0% of his salary and b spends 85% of his salary. What is the salary of b if their savings are equal?

Answer 1

Step-by-step explanation:

The salaries of A and B together is Rs. 14,000. A spend 80% of his salary and B spends 85% of his salary. What is the salary of B if their savings are equal?

Answer 2

Correct question is "The salaries of a and b together is rs. 14,000. A spend 80% of his salary and b spends 85% of his salary. What is the salary of b if their savings are equal?"

Answer:

Required salary of b is 8000 rupees.

Step-by-step explanation:

Given, salaries of a and b together is rs. 14,000.

Let salary of a is x rupees and salary of b is (14000-x) rupees.

It is also given,a spend 80% of his salary.

So,b spend

$= \frac{80}{100} \times x \\ = \frac{4x}{5} \: rupees$

So, Savings of a

$= x - \frac{4x}{5} \\ = \frac{5x - 4x}{5} \\ = \frac{x}{5} \: rupees$

Again given that b spends 85% of his salary .

So, b spend

$= (14000 - x) \times \frac{85}{100} \\ = (14000 - x) \times \frac{17}{20} \\ = 14000 \times \frac{17}{20} - x \times \frac{17}{20} \\ = 700 \times 17 - \frac{17x}{20} \\ = (11900 - \frac{17x}{20} ) \: rupees$

So, savings of b

$= 14000 - x - (11900 - \frac{17x}{20}) \\ = 2100 - x + \frac{17x}{20} \\ = (2100 - \frac{3x}{20} ) \: rupees$

According to question their savings are equal.

So,

$\frac{x}{5} = (2100 - \frac{3x}{20} ) \\ \frac{x}{5} + \frac{3x}{20} = 2100 \\ \frac{4 \times x + 3x}{20} = 2100 \\ \frac{7x}{20} = 2100 \\ 7x = 2100 \times 20 \\ x = \frac{2100 \times 20}{7} \\ x = 300 \times 20 \\ x = 6000$

Therefore, salary of a is 6000 rupees and salary of b is (14000-6000) = 8000 rupees.

This is a problem of percentage.

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