Question

The salary of a bank clerk was increased by 7%. If its present salary is rupees 8025, what was it before increment?​

Answer 1

Answer:

The salary before the increase was rupees 7500.

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Step-by-step explanation:

Let s be the salary before the increment, which is what we want.

Increasing this by 7% results in:

s + 7% of s

= s + 0.07 s

= ( 1 + 0.07 ) s

= 1.07 s

We are given that the result after the increase is 8025, so:

1.07 s = 8025

=> s = 8025 / 1.07 = 7500

Answer 2

let the salary is x before increase

ATQ

$x + 7\% = 8025 \\ x + \frac{7x}{100} = 8025 \\ \frac{100x + 7x}{100} = 8025 \\ 107x = 8025 \times 100 \\ x = \frac{8025 \times 100}{107} \\ x = \frac{75 \times 100}{1} \\ x = 7500$