Question

Find the smallest number which leaves 22,35, 48 and 61 as remainders when divided by 26, 39, 52 and 65 respectively.

Answer 1

Answer:

776

Step-by-step explanation:

(26-22,39-35,52-48,65-61) = (4,4,4,4)

LCM of (26,39,52,65) =780

Req. number= 780-4 =776

Answer 2

The given number are divides by $26,39,52and65$

Leaves remainder $22,35,48,61.$

So,

$26-22=4\\39-35=4\\52-48=4\\65-61=4$

Now, we take L.C.M of $26,39,52 and 65.$

Then LCM is $780.$

So, the smallest number is $780-4=776.$