Question

The salary of a man is increased by 20%. If he now gets Rs. 3000, his salary before the increase was.

Answer 1

Let the initial salary be x.
Now the salary is ₹3000
Increment in salary is 20%
Therefore 20= (3000-x)×100/x
On solving this equation we get the value of x to be ₹2500
Therefore his salary before the increase was ₹2500

Answer 2

Let the previous salary be x.

It is given that the present salary of the man is Rs.3,000 after the increase in salary by 20%, therefore, we have:

⇒ 20 % of x + x = Rs.3000

⇒ $\frac{20}{100}$ × x + x = 3000

⇒ $\frac{x}{5}$ + x = 3000

⇒ $\frac{x}{5}$ + $\frac{5x}{5}$ = 3000

⇒ $\frac{x+5x}{5}$ = 3000

⇒6x =3000 × 5

⇒6x = 15000

⇒ x = $\frac{15000}{6}$

⇒ X = 2500

Hence his Salary before the Increase was Rs. 2500.