The satellite of mass 1000 kg is supposed to orbit the earth at a height of 2000 km above the earth surface.the ke and pe respectively are
Answers
Answer:
The kinetic energy is 2.38 x 10¹⁰ Joules and the Potential energy is -4.76 x 10¹⁰ J
Step-by-step explanation:
Mass of earth, M = 6 x 10²⁴ kg
mass of satellite, m = 1000 kg
gravitational constant G = 6.67 x 10⁻11
Radius of earth, r = 6400 km
height of the satellite, h = 2000 km
Hence height of the satellite from center of earth(r+h) = 6400 + 2000
= 8400 km
= 84 x 10⁵ meter.
We know that kinetic energy of an object in space is given by,
KE = GMm/2(r+h)
= (6.67 x 10⁻¹¹ x 6 x 10²⁴ x 1000)/2(84 x 10⁵)
= 2.38 x 10¹⁰ Joules.
The potential energy of the system is given by:
PE = -GMm/(r+h)
= -(6.67 x 10⁻¹¹ x 6 x 10²⁴ x 1000)/(84 x 10⁵)
= -4.76 x 10¹⁰ J
Hence the kinetic energy is 2.38 x 10¹⁰ Joules and the Potential energy is -4.76 x 10¹⁰ J
Answer:k.e. =2.38×10¹° J
p.e.= 4.7×10¹° J be
Step-by-step explanation:
a)GMm/2r= 6.67×10-¹¹×6×10²⁴×1000
-----------------------------------
2×8400×1000
=0.238×10¹¹ J
b)-2×k.e.=0.47×10¹¹J