Question

The scale on a steel on a steel meter stick is calibrated at 15^@ C. What is the error in the reading of 60 cm at 27^@C ? alpha_(steel) =1.2 xx 10^-5 (.^@ C)^-1.

Answer 1

Answer:

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Answer 2

The error in the reading of 60 cm at 27°C is :

• Information given in question :

α (steel) = 1.2 x 10^-5 (°C)^-1, scale reading of meter stick = 60 cm

• We know that,

Change in length, ∆L = error in the reading = (scale reading)×α×∆T

• ∆L = L×α×∆T

∆L = 60 × 1.2×10^-5 × (27-15)

= 60 × 1.2×10^5 × 12

• ∆L = 0.00864 cm