The schematic atomic structures of three
elements X, Y and Z are given as
Х
Y
Z
Which of the following statements is/are
incorrect?
(1) Z can form ZClz and ZCI5.
(II) Y can exist in triatomic form.
(III) X and Y combine to form X3Y.
(IV) X and Z combine to form X3Z.
(V) X will gain one electron to form a stable
compound.
(VI) X and Y combine to form X2Y2, Z and Y
combine to form Y3Z2.
1 1, II, IV, V
2 I, II, III, IV, V
3 I, III, IV, V, VI
4 I, II, V, VI
+
Answers
Answered by
1
Answer:
OPTION D
Explanation:Correct option is D)
Answered by
2
Here three atoms X Y Z are given
- X has two electrons in the outermost third shell and it is Magnesium
- Y has 8 electrons in the outermost second shell and it is neon
- Z has 5 electrons in the outermost third shell and it is phosphorus
- so here Z can form ZCl₅ and ZCl₃ as pcl₅ and pcl₃ exist
- Y cannot exist in a triatomic state as it is a noble gas
- X₃Y is not possible as noble gas does not react
- X₃Z not possible
- no magnesium after gaining 1 electron does not form a stable compound
- x and Y do not form X₂Y₂ and Y₃Z₂ is also not possible
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