The second and fifth term of a geometric series are -1/2 and 1/16 respectively. Find the sum of the series up to 8 terms.
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The geometric series is known to be series with a constant ratio between the two successive terms.
The second term of geometric series (t2) = -1/2 and fifth term of geometric series is
1/16. ar= -1/2 and ar^5=1/16.
ar^5/ar = 1/16/-1/2= r^4=r.
Substituting the value of r =4 in ar= 1/16, you get tn = a((1-r^n)/(1-r)) = 4((1-2^8)/(1-8)).
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Answer:
85\128
Step-by-step explanation:
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