Question

The second and third term of an ap is 14 and 18 respectively find the sum of first 51 terms

Answer 1

Answer:

Step-by-step explanation:

The Second Term..ie, a+d=14 (1)

The Third Term ...ie, a+2d=18 (2)

Subtracting (1) from (2), we get

a+2d =18

- a+d =14

We get d = 4

Putting value of d in (1)

We get a = 10

So the AP is 10,14,18,22....

Sum51= n/2(2a+(n-1)d)

That is ... 51/2(20+200)

51/2(220)

51 × 110 = 5610

.......

Hope it helps

Answer 2

Answer:

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