Question

the second degree equation x^+4y^-2x-4y+2=0. represent​

Answer 1

Answer:

For  y∈R , x = 2

Step-by-step explanation:

x^+4y^-2x-4y+2=0 can be written as x+ 4y - 2x-4y+2=0

Solving, we get, for any value of y, x=2

Therefore, y∈R , x=2.