Question

the second hands of the watch has length 6 CM speed of end point and magnitude of difference of velocities at two perpendicular position will be
a).
$2\pi \: \: and \: \: 0 \: \: mm \: \: per \: sec$

b).
$2 \sqrt{2} and \: 44 \: \: mm \: \: per \: \: sec$

c).
$2 \sqrt{2 \: } \: \: and \: 2\pi \: mm \: persec$
d).
$2\pi \: \: and \: 2 \sqrt{2} \: mm \: per \: sec$
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Answer 1

Answer:

Angular velocity of the end point of second hand=2 pi/60 radian per second

Angular velocity of the end point of second hand=2 pi/60 radian per second

w= pi/30 radian per second

linear velocity v=r w

v=6 pi/30 cm per second

v= pi/5 cm per second in tangential direction

accelaration =v^2/r

accelaration = pi^2/25*6=pi^2/159 cm per second per second