Question

The second term from the end of the A.P. 5, 8, 11, ..., 47 is
(A) 50
(B) 45
(C) 44
(D) 41​

Answer 1

Answer:

(c)44

Step-by-step explanation:

we have l=47

common difference d = a2-a1 = 8-5 = 3

thus second term from end is

l-d i.e. 47-3 = 44

Answer 2

Given:

AP = 5, 8, 11, ... , 47

Reverse the AP:

AP = 47, ... , 11, 8, 5

Find the first term:

$\text{ First Term } = 47$

Find the common difference:

$D = T_n - T_{n-1}$

$D = 8 - 11$

$D = -3$

Find the nth term:

$a_n = a_1 + (n - 1)d$

$a_n = 47 - (n - 1)(-3)$

$a_n = 47 - (-3n + 3)$

$a_n = 47+ 3n - 3$

$a_n = 50 - 3n$

Find the second term:

$a_2 = 50 - 3(2)$

$a_2 = 50 - 6$

$a_2 = 44$

Answer: (c)  44