Question

The seek time of a disk is 30 msec. it rotates at the rate of 30 rotations per second. each track has a capacity of 300 words. the access time is (a) 47 msec (c) 60 msec (b) 50 msec (d) 62 msec

answer please

Answer 1

Access time is defined as time to access one word from memory

So, it may be the answer

1 rot = 1/30 sec

In 1 rotation ---> 100 words

For 1 word ---> 1/300 rotations

So, 1 word transfer time = 1/300*1/30 sec

So, avg access time= 30 ms(seek time)+ 1/60 sec (avg rotational latency) + 1/ 9000 sec (transfer time)

= 30+16.6667+.1111 ms

= 46.78 ms(approx)

Answer 2

Answer:

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