The segment joining (1, -3) and (4, -6) is extended a distance equal to one sixth of its own length find the terminal point.
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Answer:
Terminal point = (4.5 , -6.5)
Step-by-step explanation:
Let say Line segment Length = 6L
extended a distance equal to one sixth of its own length = 6L/6 = L
Total Length = 7L
Ratio of Line from initial Point & External Point = 7 : 1
Let say Terminal point (Tx , Ty)
Ratio : 7 : 1
Using Formula for externally dividing = (mx₂ - nx₁)/(m-n) , (my₂ - ny₁)/(m-n)
m = 7 & n = 1 (x₁ , y₁) =(1 , -3) & (x₂ , y₂) =(4 , -6)
Tx = (7(4) - 1(1) )/(7 -1) = 27/6 = 4.5
Ty = (7(-6) - 1(-3)/(7 -1) = -39/6 = -6.5
Terminal point = (4.5 , -6.5)
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