Question

the series 1/3+1/3^2+1/3^3+1/3^4+........to infinite is

A. 1/3
B. 1/2
C. 1/6
D. none of these​

Answer 1

Answer:

B)1/2

Given is a GP with common ratio 1/3

Hence sum of infinite series=a/(1-r)=(1/3)/(1-1/3)=(1/3)/(2/3)=1/2

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