Question

The series combination of two 10 ohm resistance is connected in parallel combination with a 20 ohm resistance draw the diagram of the equivalent resistance of the final combination​

Answer 1

$\huge\sf\pink{Answer}$

☞ Your Answer is 10 Ω

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$\huge\sf\blue{Given}$

✭ Two 10Ω resistors are connected in series

✭ And these two resistors are connected in parallel to a 20Ω resistor

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$\huge\sf\gray{To \:Find}$

◈ The diagram for the given case?

◈ Equivalent Resistance?

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$\huge\sf\purple{Steps}$

Diagram has been attached!!

Equivalent resistance of a series connection is given by,

$\underline{\boxed{\sf Series = R_1+R_2...R_n}}$

Substituting the given values,

➳ $\sf R_{eq} = R_1 + R_2$

➳ $\sf R_{eq} = 10 + 10$

➳ $\sf \red{R_{eq} = 20\Omega}$

Equivalent resistance of a parallel connection is given by,

$\underline{\boxed{\sf Parallel=\dfrac{1}{R_1}+\dfrac{1}{R_2}...\dfrac{1}{R_n}}}$

Substituting the values,

➝ $\sf \dfrac{1}{R_{eq}} = \dfrac{1}{R_1} + \dfrac{1}{R_2}$

➝ $\sf \dfrac{1}{R_{eq}} = \dfrac{1}{20} + \dfrac{1}{20}$

➝ $\sf \dfrac{1}{R_{eq}} = \dfrac{1+1}{20}$

➝ $\sf \dfrac{1}{R_{eq}} = \dfrac{2}{20}$

➝ $\sf \dfrac{1}{R_{eq}} = \dfrac{1}{10}$

➝ $\sf \orange{R_{eq} = 10 \ \Omega}$

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