Question

The series of lines of microwave spectrum of h35cl are separated by 6.26*10 11 hz calculate the moment of inertia of h35cl

Answer 1

Answer:

Explanation:

The first line in the pure rotational rotational spectrum spectrum of HCl

appears at 21.18cm‐1. Calculate bond length of the

molecule. Given atomic masses of H and Cl are 1.008

and 35.45 amu respectively

Answer 2

The moment of inertia of $H^{35}Cl$ is $2.68\times10^{-47}\ kg-m^2$.

Explanation:

Given that,

Frequency $f=6.26\times10^{11}\ Hz$

The spacing between adjacent lines in pure rotational spectra is equal to 2B.

We need to calculate the energy level

Using formula of line spacing energy

$E=\dfrac{hc}{\lambda}$

$E=\dfrac{hcf}{c}$

$E=h\times f$

Put the value into the formula

$E=6.63\times10^{-34}\times6.26\times10^{11}$

$E=4.15\times10^{-22}\ J$

We need to calculate the spacing between adjacent lines in pure rotational spectra

Using formula of spacing between adjacent lines

$2B=E$

Put the value into the formula

$B=\dfrac{4.15\times10^{-22}}{2}\ J$

$B=2.075\times10^{-22}\ J$

We need to calculate the moment of inertia of $H^{35}Cl$

Using formula of moment of inertia

$I=\dfrac{h^2}{8\pi^2B}$

Put the value into the formula

$I=\dfrac{(6.63\times10^{-34})^2}{8\times\pi^2\times2.075\times10^{-22}}$

$I=2.68\times10^{-47}\ kg-m^2$

Hence, The moment of inertia of $H^{35}Cl$ is $2.68\times10^{-47}\ kg-m^2$.

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