Question

The spring is compressed by a distance a and released. The block again comes to rest when the spring is elongated by a distance b. During this process

Answer 1

Answer:

Explanation:

work done by sprinn on the block =12k(a+b)2

work done by sprinn on the block =12k(a2−b2)

co-eff. of frication =k(a−b)2mg

co-eff. of frication =k(a+b)2mg

Answer :

B::C

Solution :

N//A