Math, asked by nathanaeladleymyrick, 11 months ago

the set of resolutions of sin 5x + sin 3x = square root 3 cos x for 0 degrees smaller is equal to x smaller equal to 360 degrees is .....
Plz write how to get the answer to the question that has multiple choice.
DONT ANSWER THIS QUESTION IF YOU DONT KNOW HOW TO DO IT. Ty

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Answered by IamIronMan0
0

Answer:

 \sin(5x)  +  \sin(3x)  =  \sqrt{3} \cos(x)   \\ since \\  \red{ \sin(a) +  \sin(b) = 2 \sin( \frac{a + b}{2}  \cos( \frac{a - b}{2} ) )   } \\ \\  2 \sin(4x)  \cos(x)  =  \sqrt{3}  \cos(x)  \\  \\  \cos(x)  \{ 2\sin(4x)  -  \sqrt{3}  \} = 0 \\  \\  \cos(x)  = 0 \:  \: or \:  \:  \sin(4x)  =  \frac{ \sqrt{3} }{2}  \\  \\ x =  \frac{\pi}{2} or \:  \frac{3\pi}{2}  \: and \: 4x = 2n\pi  \: \pm \frac{\pi}{3}  \\  \\ x =  \frac{n\pi}{2}  \pm \frac{\pi}{12}  = 90n + 15 \\  \\ put \:  n = 1 \: , \: 2 \: ...\\ x = 15 \:, 105 \: ,195 \:, 285

So final solution 15° ,90°, 105° ,195° ,270°, 285°

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