Question

The set of solution of quadratic equation x² + 5x + 6 = 0​

Answer 1

Answer:

${x}^{2} + 5x + 6 = 0 \\ \\ = > {x}^{2} + (3 + 2)x + 6 = 0 \\ \\ = > {x}^{2} + 3x + 2x + 6 = 0 \\ \\ = > x(x + 3) + 2(x + 3) = 0 \\ \\ = > (x + 3)(x + 2) = 0 \\ \\ either \: x + 3 = 0 \\ \\ = > x = - 3 \\ \\ or \: x + 2 = 0 \\ \\ = > x = - 2$

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Answer 2

SOLUTION

TO DETERMINE

The set of solution of quadratic equation

x² + 5x + 6 = 0

EVALUATION

Here the given Quadratic equation is

x² + 5x + 6 = 0

We find the roots as below

$\sf{ {x}^{2} + 5x + 6 = 0 }$

$\sf{ \implies {x}^{2} + (3 + 2)x + 6 = 0 }$

$\sf{ \implies {x}^{2} + 3x + 2x + 6 = 0 }$

$\sf{ \implies x(x + 3) + 2(x + 3) = 0 }$

$\sf{ \implies (x + 3) (x + 2) = 0 }$

x + 3 = 0 gives x = - 3

x + 2 = 0 gives x = - 2

Hence the required solution set is

S = { - 2 , - 3 }

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