the set of the roots of x^2 +x+a=0 exceeds a then
Answers
Answered by
23
let the roots be alpha and beta .
since the roots of this equation exceeds 'a' and the coefficient of x^2 term is >0 which implies that the graph of the equation opens upward .
therefore f(a)=a^2+a+a>0
a^2+2a>0
that means a belongs to (-infty,-2)U(0,+infty)
since the roots of this equation exceeds 'a' and the coefficient of x^2 term is >0 which implies that the graph of the equation opens upward .
therefore f(a)=a^2+a+a>0
a^2+2a>0
that means a belongs to (-infty,-2)U(0,+infty)
Attachments:
Similar questions