Question

The settlement of a group of friction piles as compared to that of a single pole is

Answer 1

The settlement of a group offriction piles is as compared to that of a single pile is (same)

Explanation:

Answer 2

Answer:

The settlement of a group of friction piles as compared to that of a single pole is more.

Explanation:

The settlement of a group of friction piles as compared to that of a single pole is more because of soil disturbances during pile installation and stress zone overlap between different piles.

The settlement of a group of friction piles is greater than that of a single pile because of soil disturbances during pile installation and pile stress zone overlap. Even when the load is the same, the settlement of a pile group is greater than the settlement of a single pile. This is because the pile group's pressure bulb is deeper than individual piles', causing the pile group to compress a larger volume of soil.

Points to Remember:

The principle of consolidation can be used to calculate pile group settlement for clayey soil.

By Skempton’s Formula:

$\(i)\frac{{{S_g}}}{{{S_i}}} = {\left( {\frac{{4B + 2.7}}{{B + 3.6}}} \right)^2} \le 16\)$

By Meyerhof’s Formula for only square pile group :

$\(ii)\frac{{{S_g}}}{{{S_i}}} = \frac{{S \times \left( {5 - \left( {\frac{s}{3}} \right)} \right)}}{{{{\left( {1 + \left( {\frac{1}{r}} \right)} \right)}^2}}}\)$

Sg = pile settlement as a group.

Si =Settlement of individual piles.

B = Pile group width.

r = a pile group's total number of rows.