the seventh part of second question
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hey here is ur answer maye....
As we know that,
(a+b+c)²=a²+b²+c²+2ab+2bc+2ca
(2x+1/x+1)²=(2x)²+(1/x)²+(1)²+ 2*2x+ 2*1/x + 2*1
=4x²+1/x²+ 1 + 4x +2/x+2
=4x²+1/x²+4x+2/x+3
As we know that,
(a+b+c)²=a²+b²+c²+2ab+2bc+2ca
(2x+1/x+1)²=(2x)²+(1/x)²+(1)²+ 2*2x+ 2*1/x + 2*1
=4x²+1/x²+ 1 + 4x +2/x+2
=4x²+1/x²+4x+2/x+3
aditya7228:
thanks but the answer in the answersheet is
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