Question

The seventh term of an AP is four times its second term and twelfth term is 2 more than three times of its fourth term .Find the progression

Answer 1

Answer:

AP: 2, 5, 8, 11, 14, 17...

Step-by-step explanation:

GIVEN:

a7= a+6d. -(i)

a7 =4(a2)

a7= 4a+4d. -(ii)

FROM (i) & (ii)

a+6d = 4a+4d. -(iii)

a12 = a+11d. -(iv)

a12 = 3(a+3d)+2. -(v)

FROM (iv) & (v)

a+11d = 3a+9d+2. -(vi)

On solving (iii) we get

2d=3a. -(vii)

On solving (vi) we get

2d=2a+2. -(viii)

ON SOLVING (vii) & (viii)

a=2

d=3

AP: 2, 5, 8, 11, 14, 17, 20, 23, 26, 29...