Question

The seventh term of an arithmetic progression is four times it's second and twelth term is two more than three times of its fourth term. Find the progression. ​

Answer 1

Step-by-step explanation:

a7=4(a2)

a12=2+3(a4)

a+6d=a+d(4)

a+6d=4a+4d

6d-4d=4a-a

2d=3a_____1

a+11d=3(a4)+2

a+11d=3(a+3d)+2

a+11d=3a+9d+2

11d-9d=3a-a+2

2d=2a+2_______2

substitute value 1in 2

3a=2a+2

3a-2a=2

a=2_____3

3a=2d

3(2)=2d

6=2d

d=6/2

d=3

therefore 2,5,8,11