Question

The shadow of a tower becomes 60 metres longer when the altitude of the sun changes from 60°to 45°. Find the height of tower. (You may use √3= 1.732)

Answer 1

Answer:

h=height

In△ABC

tan45∘=ABBC

11=ABBC=AB:BC=1:1.....(i)

In△ABD

tan30∘=ABBD

13–√=ABBD⇒AB:BD=1:3–√.....(ii)

Now,

CD=BD−BC

CD=3–√−1

3–√−1 units=60

H=1 unit=603–√−1

=603–√−1×3–√+13–√+1

h⇒30(3–√+1)m

Step-by-step explanation:

hope it will be helpful to u....

Answer 2

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