Question

The shadow of a tower is equal to its height at 10:45 am. The sun’s altitude is

a) 30 degrees b) 45 degrees c) 60 degrees d) 90 degrees​

Answer 1

Answer:

Let AB be the tower and let AC and AD be its shadows when the angles of elevation of the sum are 60

o

and 45

o

, respectively. Then,

∠ACB=60

o

,∠ADB=45

o

,CD=10 m

Let AB=h metres and AC=x metres

In right △CAB, we have,

tan60

(3 +1)

h=15+5

3m