The shadow of a tower standing on a level ground is found to be 60 m longer when
altitude is 30° than when it was 45°. Find the height of the tower.
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1
Answer:
40 underroot 3-1 Metre
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Answered by
1
Answer:
60
Case-1: Tan30=1/2=x/y, y=2x if x=height of tower, y=length of shadow.
CASE2: TAN 45=1=x/Y, Y=x
And y-Y=60,=>2x-x=60=>x=60
Height of tower is 60m
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