Question

There is a rectangular park of dimension 60m by 45m. There is a flower bed 5m wide all around it find the cost of maintaining the flower bed at rate of rs. 4 per m√2

Answer 1

cost of maintaining flower bed

=60×45/5

=300/5

=60m^2

cost=60×4 per m^2

=240 rs

Answer 2

The cost of maintaining the flower bed is Rs.4600.

Step-by-step explanation:

Given : There is a rectangular park of dimension 60 m by 45 m. There is a flower bed 5 m wide all around it.

To find : The cost of maintaining the flower bed at rate of Rs.4 per m² ?

Solution :

There is a rectangular park of dimension 60 m by 45 m.

The area of the inner rectangular park is $A=l\times b$

$A_r=60\times 45$

$A_r=2700\ m^2$

There is a flower bed 5 m wide all around it.

Length became l=60+5+5=70

Breadth became b=45+5+5=55

The area of outer park is $A=l\times b$

$A_o=70\times 55\\A_o=3850\ m^2$

Area of path = Area of outer park - Area of inner park

Area of path = 3850-2700

Area of path = 1150 m²

The cost of maintaining the flower bed at rate of Rs.4 per m².

Cost of maintaining the flower bed is

$C=1150\times 4$

$C=Rs.4600$

Therefore, the cost of maintaining the flower bed is Rs.4600.

#Learn more

N a rectangular field of dimensions 60m x 50m, a triangular park is constructed. If the dimensions of the park is 50 m,45m and 35 m, find the area of the remaining field.(ans- 2235.15 m2 )

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