the shadow of a tower standing on a level ground is found to be 30m longer when the sun's altitude is 30 degrees then when it is 60 degree find the height of the tower
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Answer:
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Step-by-step explanation:
In △ABD,
tan60
o
=
BD
AB
3
=
x
h
∴ x=
3
h
------- ( 1 )
Now in △ABC,
tan30
o
=
BC
AB
⇒
3
1
=
x+40
h
⇒ x+40=
3
h
∴
3
h
+40=
3
h [ From equation ( 1 ) ]
⇒ h+40
3
=3h
⇒ 2h=40
3
∴ h=20
3
m
∴ The height of a tower is 20
3
m.
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