Question

The shadow of a tower standing on a level ground is found to be 40m longer when the sun's altitude is 30 degree then when it was 60 degree find the height of the tower

Answer 1

Hey mate here we go

$first \: we \: have \: to \: understand \: \\ the \: problem \\ now \: shadow \: of \: tower \: is \: 40m \\ \: at \: an \: angle \: of \: 30 \: degree \\ so \: cos \alpha = \frac{adjacent \: side}{hypotines} \\ cos\: 30 = \frac{40 \: m}{hyp} \\ hyp = \frac{40}{cos \: 30} \\ hyp = 46.18 \: m \\ \: now \: the \: elevation \: has \: changed \: from \\ 30 \: to \: 60 \: degree \\ they \: told \: us \: find \: height \: of \: the \: tower \\ \: so \: now \\ sin \alpha = \: \frac{opp}{hyp} \\ sin \: 60 = \frac{opp}{46.18} \\ opp \: side = sin \: 60 \times 46.18 \\ opp \: side = 39.99 \: m \\ or \\ nearly \: equals \: to \: 40 \: m \: of \: tower \: height$

This will help you

Mark my ans as brainliest

Answer 2

$\textbf{Answer is in Attachment !}$