the shadow of a tower , standing on level ground , is found to be 45m longer when Sun's altitude is 30 degree than when it was at 60 degree. find the height of the tower.
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Answer:
22.5√3
Step-by-step explanation:
let when the angle is 60° the length of shadow be x. then length of tower be x√3
when the angle is 30° length of shadow is x+45. and length of tower will be (x+45)/√3
we know that height of tower is always same. so,
x√3=(x+45)/√3
3x=x+45
2x=45
x=22.5
height of the tower is x√3. that is 22.5√3
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