Question

The shadow of a tower when the angle of elevation. Of sun is 45degree is found to be 10m long. Longer than it was 60degree. Find height of tower​

Answer 1

Step-by-step explanation:

Let AB be the tower and let AC and AD be its shadows when the angles of elevation of the sum are 60 and 45 respectively. Then,

∠ACB=60

∠ADB=45

CD=10 m

Let AB=h metres and AC=x metres

In right △CAB, we have,

tan60 = AB/AC

√3=h/x

x=h/√3

In right △ DAB, we have,

tan45 = AB/AD

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