Question

The Shape Is Trapezium
Parallel Side 1=5cm, Parallel Side 2=11cm, height=4cm, Find Area

Parallel Side 1=6m, Parallel Side 2=14m, Find Height, Area=65 m2

Parallel Side 1=2mm Find Parallel Side 2 Height=8.25mm Area=34.65mm2

These Are Indivisual Questions

Answer 1

Answer:

$\huge{\pink{\boxed{\green{\sf{(1)AREA=32cm^{2}}}}}}$

$\huge{\pink{\boxed{\green{\sf{(2)HEIGHT=6.5m}}}}}$

$\huge{\pink{\boxed{\green{\sf{(3)P2=6.4mm}}}}}$

Step-by-step explanation:

$\huge{\pink{\boxed{\green{\underline{\red{\sf{SOLUTION-}}}}}}}$

☆ FIRST QUESTION :

$\: \: \: \: \: \: \: \: \: \: \: \: {\orange{given}} \\ {\pink{ \boxed{ \green{parallel \: side(1) = 5cm}}}} \\ {\pink{ \boxed{ \green{parallel \: side(2) = 11cm}}}} \\ {\pink{ \boxed{ \green{height = 4cm}}}} \\ \\ { \blue { \: to \: find}} \\ {\purple{ \boxed{ \red{area = ?}}}} \\ \\ \to area \: of \: trapezium = \frac{1}{2} (sum \: of \: parallel \: sides) \times height \\ \to area = \frac{1}{2} (5 + 11) \times 4 \\ \to area = 16 \times 2 \\ {\pink{ \boxed{ \green{\to area = 32cm^{2} }}}}$

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☆ SECOND QUESTION :

$\: \: \: \: \: \: \: \: \: \: \: \: {\orange{given}} \\ {\pink{ \boxed{ \green{parallel \: side(1) = 6m}}}} \\ {\pink{ \boxed{ \green{parallel \: side(2) = 14m}}}} \\ {\pink{ \boxed{ \green{area = 65m^{2} }}}} \\ \\ { \blue { \: to \: find}} \\ {\purple{ \boxed{ \red{height =? }}}} \\ \\ \to area \: of \: trapezium = \frac{1}{2} (sum \: of \: parallel \: sides) \times height \\ \to 65= \frac{1}{2} (6 + 14) \times height\\ \to 65 \times 2= 20 \times height \\ \to \frac{130}{20} = height \\ {\pink{ \boxed{ \green{\to height= 6.5m}}}}$

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☆ THIRD QUESTION :

$\: \: \: \: \: \: \: \: \: \: \: \: {\orange{given}} \\ {\pink{ \boxed{ \green{parallel \: side(1) = 2mm}}}} \\ {\pink{ \boxed{ \green{height = 8.25mm}}}} \\ {\pink{ \boxed{ \green{area = 34.65mm^{2} }}}} \\ \\ { \blue { \: to \: find}} \\ {\purple{ \boxed{ \red{parallel \: side(2)= x}}}} \\ \\ \to area \: of \: trapezium = \frac{1}{2} (sum \: of \: parallel \: sides) \times height \\ \to 34.65mm^{2} = \frac{1}{2} (2 + p2) \times 8.25 \\ \to 34 .65 \times 2 = (2 +x) \times 8.25 \\ \to \frac{34.65 \times 2}{8.25} = 2 + x\\ \to 8.4 - 2 = x \\ \to x = 6.4mm \\ {\pink{ \boxed{ \green{\to p(2) = 6.4 mm}}}}$

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