Question

the shape of a garden is rectangular in the middle and semicircular at the ends find the area and perimeter of this garden [Length of rectangle is 20_(3.5+3.5)metres]​

Answer 1

Answer:

We know that,

length of the garden=20 m

diameter of semicircle=7m,r=3.5m

(breadth of the rectangle)

Length of rectangle=20m-3.5m-3.5m

=13 m

Area of rectangle=length×breadth

=13m×7m

=91 m^2

Area of semi-circle

=1 /2×π×(3.5)^2

=1/2×22/7×35/10× 35/10

​=19.25 m^2

Area of garden=91+19.25+19.2591+19.25+19.25

=129.5\ m^2

The perimeter of garden=perimeter of rectangle+2(Perimeter of semicircle)

Perimeter of rectangle=2×length

2×26

=56 m

Perimeter of semicircle=πr

=22/7×3.5

=22/7 × 35/10​=11m

Perimeter of Garden=26m+11m+11=48m

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