Question

The shape of a garden is rectangular in the middle and semi circular at the ends as shown in the figure. find the area and perimeter of a garden. (hint: for rectangular garden, l = 13 m and b = 7m and for semi circle r = 7/2 m)

Answer 1

Area of the rectangular part = length x breadth 
=20×7=
140=
20×7=
140 sq m

Area of Semicircular portions:
 =п×r^2
= п × 7/2×7/2
= 11 × 7/2
= 77/2 cm^2

Perimeter of the shape =22+20+20=
62
=22+20+20
=62 metres

hope this helps you out!

Answer 2

$\huge\mathfrak\red {Hello \:mate}$

Here's your answer

_________________

$area \: of \: a \: square \: = > 2 \times \frac{1}{2} \times \pi {r}^{2} \\ \\ = > \frac{22}{7} \times 3.5 \times 3.5 \\ \\ = > 11 \times 3.5 \\ \\ = 38.5 {m}^{2} \\ \\ \\ \\ area \: of \: a \: rectangle \: = > l \times b \\ \\ = > 13 \times 7 \\ \\ = > 91 {m}^{2}$
Total area =》

$= > (91 + 38.5) {m}^{2} \\ \\ = > 129.5 {m}^{2} \\ \\ perimeter = > 13 + 13 + 2\pi \: r \\ \\ = >26 + 2 \times \frac{22}{7} \times 3.5 \\ \\ = > 48m$
________________

Hope it helps you