Question

.The shape of the top surface of the table is a regular octagon as shown in given figure. Find the area of top surface??​

Answer 1

Step-by-step explanation:

119

Step-by-step explanation:

• in regular octagon app sides are equal, there fore side=5cm
• octagon is divided into one rectangle and two congruent trapeziums

area of octagon = area of two congruent trapeziums +area of rectangle

$area \: of \: trapezium = \frac{1}{2} (a + b) \times hareaoftrapezium= </p><p>2</p><p>1$

(a+b)×h

area of trapezium = (1÷2)(5+13)(3) = 27 cm^2

two trapeziums so 2×27 = 54cm^2.

area \: of \: rectangle = \: l \times

$area \: of \: rectangle = \: l \times \: b$

area of rectangle =13×5 =65cm^2.

area of octagon =54+65 =119cm^2

Hope it helps !

Answer 2

Step-by-step explanation:

Step-by-step explanation:

119

Step-by-step explanation:

in regular octagon app sides are equal, there fore side=5cm

octagon is divided into one rectangle and two congruent trapeziums

area of octagon = area of two congruent trapeziums +area of rectangle

$area \: of \: trapezium = \frac{1}{2} (a + b) \times hareaoftrapezium= 2 1areaoftrapezium= </p><p>2$

(a+b)×hareaoftrapezium=21

(a+b)×h

area of trapezium = (1÷2)(5+13)(3) = 27 cm^2

two trapeziums so 2×27 = 54cm^2.

$</p><p>area \: of \: rectangle = \: l \times \: bareaofrectangle=l×b$

area of rectangle =13×5 =65cm^2.

area of rectangle =13×5 =65cm^2.area of octagon =54+65 =119cm^2

Hope it helps !

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