Question

the shopkeeper buys 250 plates for$10 each and sells 150 of them for 12$ each. And the rest were sold to a cafe for a total of $800 . Calculate the total profit earned by the shopkeeper!!​

Answer 1

Answer:

2x2 - 6x +3; -3x -x-4: 1+ 2x - 3x? add the following algebraic expression using both horizontal method and vertical method. did you get the same answer2x2 - 6x +3; -3x -x-4: 1+ 2x - 3x? add the following algebraic expression using both horizontal method and vertical method. did you get the same answer

Answer 2

Given :-

• The shopkeeper buys 250 plates for$10 each.

• Sells 150 of them for 12$ each and the rest were sold to a cafe for a total of $800.

To Find :-

• Profit earned by shopkeeper.

Solution :-

Given that,

• Cost price of 1 plate = $ 10

So,

• Cost Price of 250 plates = 250 × 10 = $ 2500

Now,

• Selling Price of 1 plate = $ 12

So,

• Selling Price of 150 plates = 150 × 12 = $ 1800

• And remaining 100 plates sold for $ 800

So,

• Selling Price of 250 plates = 1800 + 800 = $ 2600

Thus,

We have

• Cost Price of 250 plates = $ 2500

• Selling Price of 250 plates = $ 2600

Since,

• Selling Price > Cost Price

It implies,

• There is profit in this transaction.

We know

• Profit = Selling Price - Cost Price

It implies,

• Profit = 2600 - 2500 = $ 100

Hence,

• Shopkeeper earned profit of $ 100

$\begin{gathered}\: \: \: \: \: \: \begin{gathered}\begin{gathered} \footnotesize{\boxed{ \begin{array}{cc} \small\underline{\frak{\pmb{ \red{More \: Formulae}}}} \\ \\ \bigstar \: \bf{Gain = \sf S.P. \: – \: C.P.} \\ \\ \bigstar \:\bf{Loss = \sf C.P. \: – \: S.P.} \\ \\ \bigstar \: \bf{Gain \: \% = \sf \Bigg( \dfrac{Gain}{C.P.} \times 100 \Bigg)\%} \\ \\ \bigstar \: \bf{Loss \: \% = \sf \Bigg( \dfrac{Loss}{C.P.} \times 100 \Bigg )\%} \\ \\ \\ \bigstar \: \bf{S.P. = \sf\dfrac{(100+Gain \%)(or)(100 - Loss\%)}{100} \times C.P.} \\ \: \end{array} }}\end{gathered}\end{gathered}\end{gathered}$