Question

The short and long hand of the clock are 4 cm and 6 cm respectively. find the sum of the distance travelled by their tips in 2 days

Answer 1

Answer:

6×12=72÷2=32answer**The short and long hand of the clock are 4 cm and 6 cm respectively. find the sum of the distance travelled by their tips in 2 days **

Answer 2

Answer:

Short hand completes 4 rotations in 2 days, then distance travelled by tip is,

$4×2\pi \: r = 4×2 \times \frac{22}{7} \times 4 = \frac{704}{7} cm$

long hand covers 48 rotations,

$48×2\pi \: r = 48×2 \times \frac{22}{7} \times 6 = \frac{12672}{7}cm$

Total distance is,

$\frac{704+12672}{7} = \frac{13376}{7}$

Distance is 1910.8571...cm

hope it helps you...