The short and long hands of a clock are 4cm and 6 cm. Find the sum of distances traveled by their tip in 48 hours
Answers
Answered by
0
distance travelled by short hand is 2πr for twelve hrs
for 48 hrs distance=4*2*22/7*4
704/7
distance travelled by long hand for 48 hrs is 4*2πr
4*2*22/7*6=1056/7
sum of both hands is 704+1056/7
1760/7
251.42cm
for 48 hrs distance=4*2*22/7*4
704/7
distance travelled by long hand for 48 hrs is 4*2πr
4*2*22/7*6=1056/7
sum of both hands is 704+1056/7
1760/7
251.42cm
Answered by
1
Answer:
Step-by-step explanation:
Length of minute hand =6cm
Distance traveled by its tip in 48hours=2πr*48
2*3.4*6*48= 1808.64cm
Similarly,with hour hand of 4cm
Distance traveled by its tip in 48hours=2*3.4*4*48= 1205.76cm
Total distance= 1808.64+1205.76
3014.4cm
Similar questions