Math, asked by urmilade689, 23 hours ago

The short hand and long hand of a clock are 10 cm and 12 cm long respectively. The sum of the distances travelled by their tips in one day is ​

Answers

Answered by shiwkishor
6

Step-by-step explanation:

Annexure may be referred to for solution.

Attachments:
Answered by RvChaudharY50
5

Given :- The short hand and long hand of a clock are 10 cm and 12 cm long respectively.

To Find :- The sum of the distances travelled by their tips in one day is ?

Formula used :-

  • Short hand is hour hand which complete two rounds in one day .
  • Long hand is minute hand which complete 24 rounds in one day.
  • Circumference of circle = 2πr
  • π = 3.14

Solution :-

Short hand :- (Hour hand)

→ Length = Radius = 10 cm

So,

→ Distance travelled in one round = circumference of circle = 2πr = 2 × 3.14 × 10 = 6.28 × 10 = 62.8 cm

then,

→ Distance travelled in two rounds = 2 × 62.8 = 125.6 cm --------- Equation (1)

Long hand :- (Minute hand)

→ Length = Radius = 12 cm

So,

→ Distance travelled in one round = circumference of circle = 2πr = 2 × 3.14 × 12 = 75.36 cm

then,

→ Distance travelled in 24 rounds = 24 × 75.36 = 1808.64 cm --------- Equation (2)

adding Equation (1) and Equation (2) we get,

→ Total distance travelled by both hands of clock in one day = 125.6 + 1808.64 = 1934.24 cm (Ans.)

Hence, The sum of the distances travelled by their tips in one day is equal to 1934.24 cm .

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