Math, asked by kalpesh7498, 11 months ago

The shortest distance from the point M(–7, 2) to the circle x2 + y2– 10x – 14y – 151 = 0 is

Answers

Answered by Anonymous

7

Step-by-step explanation:

(-7)^2+2^2-10×(-7)-14×2-151

=49+4+70-28-151

=-56 units is the distance

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